LÖVE

Posted: **Fri May 08, 2015 7:31 pm**

Hey, been wondering this for some time. How do I compare a number too see if it's decimal or an integer?

Posted: **Fri May 08, 2015 7:56 pm**

if math.floor(number) == number then
  -- is integer
else
  -- non-integer
end

There may be some robustness issues of course but it should work as
long as the number is not very large or small.

Posted: **Fri May 08, 2015 9:15 pm**

If that's what you want to do, ivan's solution should work just fine. It sounds to me however like something you would never need to do. If you need an integer, but aren't sure it is one, just use math.floor(datNumber) (or math.floor(datNumber + 0.5) if you want to round it).

Posted: **Fri May 08, 2015 10:23 pm**

You could also check if a number is an integer by doing this:

Code: Select all

function isInteger( x )
     return x % 1 == 0
end

Posted: **Sat May 09, 2015 5:50 pm**

Both solutions work for me.

Basically I was trying to make this kind of grid:

Code: Select all

{
{w,w,w,w,w,w,w,w,w}
{w,0,0,0,0,0,0,0,w}
{w,0,i,0,i,0,i,0,w}
{w,0,0,0,0,0,0,0,w}
{w,0,i,0,i,0,i,0,w}
{w,0,0,0,0,0,0,0,w}
{w,0,i,0,i,0,i,0,w}
{w,0,0,0,0,0,0,0,w}
{w,w,w,w,w,w,w,w,w}
}                           -- i = indestructable
                            -- w = wall
                            -- 0 = floor

+1 point for anyone who guesses right what kind of clone I'm making?

Posted: **Sun May 10, 2015 2:01 pm**

Bindie wrote:+1 point for anyone who guesses right what kind of clone I'm making?

Just a shot in the dark

Posted: **Sun May 10, 2015 2:20 pm**

Bull's eye, +1!

Posted: **Sun May 10, 2015 3:35 pm**

Why would you need to know if a number is an integer or not to produce such a grid?

Posted: **Sun May 10, 2015 3:52 pm**

T-Bone wrote:Why would you need to know if a number is an integer or not to produce such a grid?

My best guess is he halfed the x coordinate and checked whether it was integer?

In that case he should've just take the modulo-2:

Code: Select all

if x%2 == 0 then -- x is even end

Posted: **Sun May 10, 2015 6:58 pm**

S0lll0s wrote:My best guess is he halfed the x coordinate and checked whether it was integer?

In that case he should've just take the modulo-2:
Code: Select all
if x%2 == 0 then -- x is even end

That's right, I found an easier solution though using false and true values.

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