[SOLVED]emptying a table completely

[Vimm]

I want to remove every value thats in a table, but I can't figure out how, I tried making a variable that increments everytime something is added to the table, then making a for loop that, if the number of the object spawned is greater than or equal to 0, it removes 1 and decrements, then loops, heres the code I used

Code: Select all

for i, v in ipairs(listOfPillars) do
			if numberOfPillars >= 0 then
				table.remove(listOfPillars, 1)
				numberOfPillars = numberOfPillars - 1
			end
		end

this, however, only seems to get rid of the first 2 pillars spawned, not all the ones on the screen :/ what am I missing? Am I even on the right track?

[airstruck]

The most straightforward way would be something like this (assuming you only use numeric indices):

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for i = 1, #listOfPillars do listOfPillars[i] = nil end

If you don't have too many references to that table floating around, you could just do listOfPillars = {} and update any references.

[Vimm]

The most straightforward way would be something like this (assuming you only use numeric indices):

Code: Select all

for i = 1, #listOfPillars do listOfPillars[i] = nil end

If you don't have too many references to that table floating around, you could just do listOfPillars = {} and update any references.

ayye that worked, thanks

geez im so bad with for loops and tables still

[airstruck]

Time to read PIL

[Vimm]

Time to read PIL

Haha I know I should but I just can't get around to it XD
How do I change the thread to solved?

[zorg]

Edit your first post, and put [Solved] before the subject.

[Vimm]

Edit your first post, and put [Solved] before the subject.

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