[SOLVED]Simple Countdown doesnt work.

[W3LF]

Hello everybody, I'm new to Lua programming.
I'm trying to work on a simple countdown, but Love gives me an error:
--
Error
Syntax Error: main.lua:16: 'then' expected near '='
--

here is my simple code:

function love.load()
love.graphics.setBackgroundColor(255, 255, 255)
totalTime = 30
gameOver = false
end

function love.update(dt)
totalTime = totalTime - dt
if totalTime <= 0 then
gameOver = true
end
end

function love.draw()
if gameOver = true then
love.graphics.print("GAME OVER", 100, 100)
end
end

I don't get why does Love tells that the syntax is wrong :/

[bartbes]

Please use code tags next time, as it makes the code more readable (and preserves identation).
As for the issue, in love.draw your code says "if gameOver = true then", that should be ==, rather than =.

[W3LF]

Uh, i'm so stupid.

Btw, I use tags, it's just Copy-Paste's effect, i'll be more careful next time

[zorg]

Code: Select all

 These kind of tags: [code]

[/code]

[Kasperelo]

Code: Select all

if gameOver = true then

should be

Code: Select all

if gameOver == true then

-
Alternatively, you can simply write

Code: Select all

if gameOver then

which does the same thing

[W3LF]

Code: Select all

 These kind of tags: [code]

[/code]

Oh, alright, sorry.