I've been working on the sequel to my previous game (which was never posted here) for a couple of months now and I'm feeling confident about showing it here. :awesome: To sum up, it's a 2d platformer/jump 'n' run with a simple (and silly) story to break up the gameplay. Just like its predecessor. Yo...

After working on this utility for a long time and extensively using and extending it myself, I finally decided to share and publish it. :ultrahappy: You can find its GitHub repo here. In a nutshell, it will look about like this when used: https://i.gyazo.com/3a9550c6ab5a50dd0cd6fd5c7bd22294.png Don'...

zorg wrote:

DPlayer234 wrote:This code will now make it return 1 if both "v[3] == 1" and "v[3] == 3" return true (the "or 1"-part does that).

You mean it'll return 1 if both return false; if both returned true, then it'd set the value to the first in the chain.

Oh yeah, right. Of course. My bad.

The solution is pretty simple. This: (lines 225-228) for i,v in pairs(CurrentLevel.Enemies) do v[1] = v[3] == 1 and v[1] + 1 or v[3] == 3 and v[1] - 1 v[2] = v[3] == 2 and v[2] + 1 or v[3] == 4 and v[2] - 1 end would set v[1] to false if neither "v[3] == 1" or "v[3] == 3" return ...