(A lua only question)

[Evil_Bartek]

I made a dec to binary converter a while ago and i want to convert it back.
So i thought of this method:

the binary is 11000100
The rightmost digit represents how many 1s (in this example 0)
The next digit left represents how many 2s (in this example 0)
The next digit left represents how many 4s (in this example 1)
The next digit left represents how many 8s (in this example 0)
The next digit left represents how many 16s (in this example 0)
The next digit left represents how many 32s (in this example 0)
The next digit left represents how many 64s (in this example 1)
The next digit left represents how many 128s (in this example 1)

then you add: 4+64+128 = 196 which is right.

Any idea how to do that in lua?
I know how to get the love2d stuff done.

[nevon]

Code: Select all

function Bin2Dec(s)
    local num = 0
    local ex = string.len(s) - 1
    local l = 0
    
    l = ex + 1
    for i = 1, l do
        b = string.sub(s, i, i)
        if b == "1" then
            num = num + 2^ex
        end
        ex = ex - 1
    end
    
    return string.format("%u", num)
    
end

Source

[MarekkPie]

Beat me to it.

[bartbes]

Code: Select all

tonumber("11000100", 2) --> 196

[MarekkPie]

Even better. Can easily go to octal and hexidecimal.